Capacitor Discharge Time Formula Euler

AI Thread Summary
The discussion centers on understanding the application of Euler's constant raised to a fractional exponent in capacitor discharge calculations, specifically resulting in a voltage of 958mV. Participants confirm the calculations are correct, emphasizing the exponential nature of capacitor charging, described by the formula Vc=Vf(1-e-t/T). There is a request for clarification on the fractional exponent's role in achieving the result, with a suggestion to watch a teaching video for further explanation. The conversation also touches on the challenges of finding educational resources in Portuguese, particularly regarding the Neper constant and logarithmic calculations. Overall, the thread highlights a collaborative effort to clarify mathematical concepts related to capacitor discharge.
NickTesla
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I would like to understand how the Euler constant elevated to fractional exponent gave this result? 958mV someone please!?
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You did not give enough information for us to check everything, but the calculation is correct (I checked it on my old HP calculator).
 
It is because my doubt is the fractional exponent, do not know why has this result!
958mV no final entendeu!? Obrigado!
 
Personal My question is in Euler's constant raised to a fractional exponent!
Why and how ?? I do not know calculate HP, it's good we mastered without having to use HP,

I have a teaching video, but honestly I still do not understand if you want to see the video? I have!
 
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Charging of a capacitor is an exponential
event. Voltage across capacitor rises exponentially as
Vc=Vf(1-e-t/T). Time t is in the exponent, hence the part e-t/T is responsible for the exponential increase in voltage w.r.t time.
 
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OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
 
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Yes! , I understand, but using numbers,
Watch this video!
 
Svein said:
OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
 
https://www.youtube.com/watch?v=JHHikLqJuYk
 
  • #10
Svein said:
OK. Let us take it in steps:
  1. \frac{10}{47}= 0.212765957
  2. e^{-0.212765957}=0.808345302
  3. 1- 0.808345302=0.191655
  4. 5 \cdot 0.191655 = 0.958273
Sven Wonderfully Thank you!
 
  • #11
NickTesla said:
Sven Wonderfully Thank you!
Obrigado!
 
  • #12
Personally, I'll be honest, here in South America (Brazil) I doubt that the Brazilian has a video explaining speaking Neper calculation on youtube to calculate the potentiation, constant = e ^ -0.212765957,
I doubt (I dúvi [do] D + O = DO = DEODO talking!). Kkk! I doubt DEODO is when we doubt very much! is the Brazilian way of speaking! My God there are only understand potentiation, that's all, and I going crazy, studying (Mantissa) studies (Mantissa) kkkk lol (mathematics: decimal part of a logarithm) !:book::micoscope:
(Matematicas: decimal part of a logarithm)! I wanted the help of North America, if possible help from the American continent LOL kkkk:oldbiggrin::partytime::bow::headbang::headbang::headbang:

only thing i got! and I get it! Was this here!

but not taught 10 ^ 0,3010

how does it do??:headbang::headbang::headbang::oldgrumpy::oldgrumpy::oldgrumpy:
 
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