Capacitor Energy With Different Dielectrics

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SUMMARY

The discussion focuses on calculating the maximum energy stored in a capacitor using different dielectric materials: rubber, glass, and teflon, with a constant potential difference of 12.0 V. The capacitance formula C = K*A0ε0/d is applied, where rubber (κ = 6.7) yields the highest capacitance due to its favorable K/d ratio. The user initially miscalculated the energy stored due to incorrect area unit conversion, which was clarified by other forum members. The corrected energy storage calculation resulted in 9.72 * 10-6 J for rubber.

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  • Proficiency in unit conversions, particularly area from cm2 to m2
  • Knowledge of the equations for capacitance (C) and potential energy (PE)
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Homework Statement



Two parallel plates are connected to a battery which maintains a constant potential difference of 12.0 V. The distance between the plates can be varied and there are three plates of different dielectric materials available: rubber (0.40 mm, κ = 6.7), glass (4 mm, κ = 7) and teflon (3 cm, κ = 2.1). The area of the plates is 91 cm2. What is the maximum energy that can be stored in the capacitor using one of the three materials?

Homework Equations



C = K*A0ε0/d

PE = CV2/2

The Attempt at a Solution



The highest energy stored will be in the system with the greatest capacitance; i.e., where the ratio of K/d is the largest. Rubber's K/d is greater than the other options, so rubber as the dielectric should produce the greatest capacitance.

C = (6.7)(.91)(8.854 * 10-12) / .0004

C = 1.35 * 10-7 F

With the capacitance, the energy can be calculated:

PE = CV2/2

PE = (1.35 * 10-7)(122)/2

PE = 9.72 * 10-6 J
This answer isn't correct, and I'm not sure why. My first concern was that I might not have converted all the units appropriately, but I've diligently checked, and I'm pretty sure they are all correct. (But the undying suspicion is that they are not is, well, undying.)

I am assuming I am missing something conceptually. Any guidance would be very much appreciated.

PS: I'm new to posting here, so if I break some sort of rule or violate some sort of expectation, please feel free to enlighten me. I've lurked around a great deal as I've progressed through my first few physics classes, and I have a great deal of respect for everyone here.
 
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Check your conversion for the plate area. How many square centimeters are there in a square meter?
 
gneill said:
Check your conversion for the plate area. How many square centimeters are there in a square meter?

Ah, I see... I was basically only converting one "side" of the square. Guess my intuition was more correct than I gave it credit for.

Thanks--fixing this gave me the correct result. Glad I wasn't misunderstanding the general concept.
 

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