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The formula which describes the charge Q(t) on the left hand side plate of the first capacitor is A.sin(wt). I need to find the formula which describes the charge on the right hand plate of the last capacitor (no.3).

Attempt:

I tried working in currents I. So the equation above becomes wAcos(wt). The total impedance Z of the 2nd segment is Z_1.Z_2 / Z_1 + Z_2, which is just R / ( 1 + RwC ).

I figured that the current at the last capacitor would be V / Z = I, where V is the potential. Since the current and voltage are out of phase by 90 degrees in the first capacitor, I got V = A.cos(wt).

So From this I get I, and just integrate to get Q(t). I dont think Im correct tho. I always have trouble with electrical circuits. Could someone perhaps point me in the right way????