1. The problem statement, all variables and given/known data Two capacitors A and B with capacitance 3 μF and 2 μF are charged to potential difference of 100 V and 180 V respectively. These two capacitors are connected to an uncharged capacitor of 2 μF using a switch as shown in the diagram. Determine the final charge on each capacitor when the switch is closed. ( please refer the figure (attachment))..... 2. Relevant equations Q=CV 3. The attempt at a solution the actual method is by charge conservation and Kirchhoff Loop rule.. ..but i tried a different method and terribly failed! BEFORE THE SWITCH IS ON, i tried to find the net equivalent capacitance of the 2 capacitors lying in the bottom,and then,WHEN SWITCH IS ON ,by assuming that a charge (q') flows to the uncharged capacitor from the NET charged capacitor till the capacitors are at the same potentials.But i ended up with the wrong answer....so my method fails......but why???....i think i went wrong in the first step itself...i feel i shouldnt have found the net capacitance using series formula......but why not??? where did i go wrong actually? please help. in brief, why cant we apply series combination formula in an open circuit??