NascentOxygen said:Certainly you can combine them. Regardless of all else, if they are in series then it's always true that 1/C = 1/C1 + 1/C2
That gives you the capacitance that behaves equivalently, but you have yet to determine the initial charge it should have so as to lead to identical circuit current & voltage when the switch gets closed.
A capacitor is an electronic component that stores electric charge and is commonly used in electronic circuits to regulate the flow of electricity.
A capacitor works by storing electric charge between two conductive plates separated by an insulating material, also known as a dielectric. When a voltage is applied across the capacitor, one plate accumulates positive charge while the other accumulates negative charge.
Capacitors have a variety of uses in electronic circuits, including storing energy, smoothing out voltage fluctuations, and blocking or passing certain frequencies of electric current.
In a series combination of capacitors, the total capacitance is equal to the reciprocal of the sum of the reciprocals of each individual capacitor. In an open circuit, the current is zero, meaning that the capacitance of the entire series combination would also be zero, rendering it useless.
Yes, capacitors in a series combination can be used in a closed circuit. However, the total capacitance will be less than the capacitance of the individual capacitors. This is because the effective capacitance of capacitors in series is always less than the smallest individual capacitance.