How Do You Solve Capacitance and Voltage in This Capacitor Network?

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To solve the capacitor network problem, first, determine the equivalent capacitance of the 7.0 μF and 3.0 μF capacitors in series, which is calculated as 1/(1/7 + 1/3). This series combination is then added to the 4.4 μF capacitor in parallel to find the net capacitance. For part b, the total voltage of 24 V is applied across the network, and the voltage across the 4.4 μF capacitor can be calculated using the formula V = Q/C, where Q is the charge. The voltage across the series combination can be found using the relationship between charge and capacitance for each capacitor. Understanding these steps is crucial for accurately solving the problem.
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I am really confused on how to solve this Physics question. I attempted the first one but is wrong for some reason.

A 7.0 micro F and a 3.0 micro F capacitor are connected in series and this combination is connected in parallel with a 4.4 micro F capacitor.

a) What is the net capacitance?
b) If 24 V is applied across the whole network, calculate the voltage across each capacitor.

For part a, i tried to do:

1/Net Capacitance = 1/(7+3) + 1/4.4 and got 3.056 for the net capacitance. However, it is saying that i am wrong. Can you tell me what i am doing wrong?
 
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First find the capacitance of the series combination. What is it?
 
haha nvm i get part a

for part a i got 1/7 + 1/3 and took the inverse of that then added it to 4.4 XD

how do you do part b?
 
You have a 1/7 + 1/3 μF capacitor in parallel with a 4.4 μF capacitor. What is the voltage across the 4.4 μF capacitor? What is the voltage across the 1/7 + 1/3 μF combination capacitor?
 

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