Car hits brick wall, find inital speed of car

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An automobile with a mass of 2000 kg collides with a brick wall, compressing its bumper, which acts as a Hooke's-law spring with a spring constant of 5 × 10^6 N/m by 1.67 cm. The work done on the spring during the collision is calculated using the formula for spring energy, resulting in 69,722.5 J. The change in kinetic energy of the car is equal to this work done, allowing for the calculation of the initial speed of the car. After correcting a unit conversion error, the initial speed is determined to be approximately 0.835 m/s. The discussion emphasizes the importance of correctly applying physics formulas and unit conversions in solving the problem.
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Homework Statement


An automobile of mass 2000 kg is driven into
a brick wall in a safety test. The bumper
behaves like a Hooke’s-law spring. It has an
effective spring constant of 5 × 106 N/m, and
is observed to compress a distance of 1.67 cm
as the car is brought to rest.
What was the initial speed of the automo-
bile?
Answer in units of m/s.


Homework Equations


\DeltaKE = (1/2)mvf2-(1/2)mvi2
Wapplied to spring=(1/2)kxf2-(1/2)kxi2


The Attempt at a Solution



\Deltax = -0.167m

SPRING.jpg

Wapp=(1/2)kxf2-(1/2)kxi2
Wapp=(1/2)(5x106)(-0.167)2-(1/2)(5x106)(0)2

Wapp = 69722.5 J

Vf = 0 (because the car is brought to rest)
m = 2000 Kg

\DeltaKE = 69722.5 J =(1/2)(2000)(0)2-(1/2)(2000)vi2

69722.5 J = -(1000)vi2
vi2 = (69722.5/-1000)

vi = (-69722.5/1000)1/2

and here i came to a dead end with a non-real answer. Err..
am I at least going in the right direction. I must have my sign off somewhere. I just want to know if I'm approaching the problem correctly.
 
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The change in the kinetic energy of the car, the energy it loses, is transferred to the buckle.
The car goes from v to zero so its change in kinetic energy is simply ½mv²
If the bumper behaves as a Hooke's Law spring, then the energy absorbed by it is given by a formula involving k, the spring constant, and x the distance it compresses.
You have all the information [m,k and x] to calculate v.
Do you know the spring formula?
 
do you mean
Fspring=-kx

and the work done by a spring is
Ws=\int(-kx) dx = 1/2kxf2-1/2kxi2
 
Last edited:
AHinkle said:
do you mean
Fspring=-kx

and the work done by a spring is
Ws=\int(-kx) dx = 1/2kxf2-1/2kxi2

That's it. It's just ½kx² here where x is the compression. Equate the work done to the loss in k.e. of the car.
 
1/2kxf2-1/2kxi2=1/2mvi2

1/2(5x106)(-.0167)2-1/2(5x106)(0)2=1/2(2000)vi2

vi = .835m/s? aww crap... i got a sign or something mixed up somewhere or i just don't understand what orientation i need to put all the parts together in
 
actually i checked the answer and .8350 m/s is correct! I found out what i did wrong. I converted from centimeters to meters incorrectly in my first work calculation and that threw everything off.
 
Yes, the answer is fine. :)
 
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