Car Runs Out of Gas: Calculate Speed After Coasting Down Hill

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The discussion centers on calculating the speed of a 1500 kg car after it coasts down a hill, having initially approached the hill at 10.0 m/s. The conservation of energy principle is emphasized, indicating that the car's initial kinetic energy converts to potential energy as it ascends and then back to kinetic energy while descending. The correct equation for this scenario is 1/2*m*(v_1)^2 + mgh_1 = 1/2*m*(v_2)^2 + mgh_2, but accurate calculations require knowing the hill's height and ensuring consistent units. Participants suggest double-checking calculations, using correct values, and visualizing the problem with diagrams for clarity. Ultimately, the final speed after coasting depends on the initial speed, hill height, and car mass.
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A 1500 kg car is approaching a hill shown in the diagram at 10.0 m/s when it suddenly runs out of gas. Assuming the car makes it to the top by coasting, what is the car's speed after coasting down the other side?

I tried using 1/2*m*(v_1)^2+mgh_1= 1/2*m*(v_2)^2+mgh_2 but didn't get the right answer.
 

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Well, this looks like a straight conservation of energy problem, with a little kinematics, maybe. The speed is affected by how fast the car is moving on top.. figure out how much energy the car has on top of the hill... then try conservation of energy again.
 


The equation you used, 1/2*m*(v_1)^2+mgh_1= 1/2*m*(v_2)^2+mgh_2, is the correct equation to use in this scenario. However, there may be a mistake in your calculations or some information missing that is causing you to not get the correct answer. To solve this problem, you will need to use the conservation of energy principle, which states that energy cannot be created or destroyed, only transferred from one form to another. In this case, the initial kinetic energy of the car is converted into potential energy as it goes up the hill, and then back into kinetic energy as it goes down the other side.

To solve for the final speed, you will need to know the height of the hill (h_1 and h_2) and the gravitational acceleration (g). You also need to make sure that the units for all the variables are consistent (e.g. if height is in meters, make sure g is in m/s^2). Once you have all the necessary information, plug in the values into the equation and solve for v_2. Remember to use the correct signs for potential energy (positive when going up, negative when going down) and to take into account the initial velocity of the car (10.0 m/s).

If you are still having trouble getting the correct answer, double check your calculations and make sure you are using the correct values for the variables. It may also be helpful to draw a diagram and label all the given information to visualize the problem better. Keep in mind that the final speed after coasting down the other side will depend on the initial speed, the height of the hill, and the mass of the car.
 
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