Car Tire Skidding: Deceleration with uk = 0.8

Thread starter physics_10
Start date Oct 23, 2010
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The discussion centers on calculating the deceleration of a car with locked wheels skidding on a flat surface, given a coefficient of kinetic friction (uk) of 0.8. To determine the deceleration, Newton's second law is applied, where the force of friction is the product of the coefficient of friction and the normal force. The normal force equals the weight of the car, allowing for the calculation of deceleration as a function of the frictional force. Participants express confusion about solving the problem with limited information, emphasizing the need to utilize the provided coefficient effectively. Understanding the relationship between friction and deceleration is crucial for solving this scenario.

Oct 23, 2010

physics_10

Suppose that the coefficient of kinetic friction of the rubber of a car tire and the street is uk = 0.8. What is the deceleration of the car on a flat street if the driver brakes sharply, so all the wheels are locked and skidding?

I'm not sure how I am supposed to solve this if only the uk is provided?

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Oct 23, 2010

PhanthomJay

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Use Newton's 2nd law.

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