Carnot Engine Work Output w/Monatomic Gas: 288K to 497K

AI Thread Summary
A Carnot engine using a monatomic gas operates between temperatures of 288K and 497K, performing 800 J of net work. The discussion centers on calculating the heat absorbed (QH) and heat released (QC), as well as the engine's efficiency. The efficiency formula for a Carnot engine is provided, indicating it can be derived from the work output and heat absorbed. Participants express uncertainty about the missing information needed for calculations but acknowledge the importance of identifying QH and QC. Understanding these concepts is essential for solving the problem effectively.
brockjensen
Messages
3
Reaction score
0

Homework Statement



A Carnot engine working with a monatomic gas operating between two temps, 288K and 497K. The engine performs 800 J of net work.



Homework Equations



Q = nRT ln (V final/V initial)


The Attempt at a Solution


I don't have enough info for the above equation. I know I am missing something just not sure what.
 
Physics news on Phys.org
What are you to find?
 
rock.freak667 said:
What are you to find?

Sorry, that would have been helpful.

Need to find heat absorbed and heat released, also efficiency, but I think I got that one
 
Yeah that would be helpful huh?

Need to find heat absorbed and heat released, also efficiency but I think I figured that out.
 
You should know that for a Carnot engine, the efficiency is given by

\eta = \frac{W}{Q_H}=1 - \frac{T_C}{T_H}


Now that you know this, I think you can easily find QH
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top