Carnot Engine Work Output w/Monatomic Gas: 288K to 497K

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Homework Help Overview

The discussion revolves around a Carnot engine utilizing a monatomic gas, operating between temperatures of 288K and 497K, with a net work output of 800 J. Participants are exploring the relationships between heat absorbed, heat released, and efficiency in the context of thermodynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants express uncertainty regarding the necessary information to apply the relevant equations. There are inquiries about what specific values need to be calculated, including heat absorbed, heat released, and efficiency.

Discussion Status

Some participants have provided guidance on the efficiency formula for a Carnot engine, suggesting that this could lead to finding the heat absorbed. However, there is no explicit consensus on the next steps or the completeness of the information needed.

Contextual Notes

There is a noted lack of information regarding the number of moles of gas and the specific volumes, which may be critical for applying the ideal gas law in this context.

brockjensen
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Homework Statement



A Carnot engine working with a monatomic gas operating between two temps, 288K and 497K. The engine performs 800 J of net work.



Homework Equations



Q = nRT ln (V final/V initial)


The Attempt at a Solution


I don't have enough info for the above equation. I know I am missing something just not sure what.
 
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What are you to find?
 
rock.freak667 said:
What are you to find?

Sorry, that would have been helpful.

Need to find heat absorbed and heat released, also efficiency, but I think I got that one
 
Yeah that would be helpful huh?

Need to find heat absorbed and heat released, also efficiency but I think I figured that out.
 
You should know that for a Carnot engine, the efficiency is given by

[tex]\eta = \frac{W}{Q_H}=1 - \frac{T_C}{T_H}[/tex]


Now that you know this, I think you can easily find QH
 

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