Car's Kinetic Energy After Doubling Linear Momentum

AI Thread Summary
The discussion centers on calculating the new kinetic energy of a car after its linear momentum is doubled while maintaining its mass. The initial kinetic energy is given as 1.00 x 10^5 J. When the momentum is doubled, the velocity also increases, leading to a quadrupling of the kinetic energy based on the relationship E = ½mv². Consequently, the new kinetic energy is calculated to be 4.00 x 10^5 J. This demonstrates the direct relationship between momentum and kinetic energy in physics.
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The kinetic energy of a car moving down a road is 1.00 x 10^5 J. The car suddenly doubles the magnitude of it's linear momentum vector without changing it's mass. What is the new value of the car's energy?
A) 9.00 x 10^5 J
B) 4.00 x 10^5 J
C) 6.00 x 10^5 J
D) 9.00 x 10^6 J
E) none of the above!

P_>=mv_>

I thought ke was a scalar and momentum was a vector. Can this problem be done?
 
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Yes, it can be done.
Are you familiar with the trick of seeing immediately that
when E = ½mv², then
- doubling m causes E to double
- doubling v causes E to quadruple
One way to see it is to replace v with (2v) and write the 2 in red;
you see that (2v)² is 4v² so the ½mv² has changed to 4(½mv²).

That is the technique to deal with your question.
You have p = mv so v = p/m
Ask yourself how doubling p affects v.
Then how that affects KE.
 
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