Cartesian Vectors and Quadrilaterals

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I have no clue where to start on this question.
Use Cartesian vectors in two-space to prove that the line segments joining midpoints of the consecutive sides of a quadrilateral form a parallelogram.

Atm all i can deduce from the information is that vectors 2A+2B+2C+2D=0 therefore midpoint vectors A+B+C+D=0 and to prove that it is a parallelogram A+B//C+D and vector A+C//B+D
 
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Since this talks about using parallelograms, how about using the "parallelogram law" for vector addition? That is, that for vectors u and v, u+ v is the length of the longer diagonal of the parallelogram having u and v as sides and u- v is the length of the shorter diagonal.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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