How can I increase the distance of a catapult launch with a hollow ball?

  • Thread starter Thread starter Amenable Me
  • Start date Start date
  • Tags Tags
    Ball Catapult
AI Thread Summary
To increase the distance of a catapult launch with a hollow plastic ball, experimenting with launch angles is essential, with suggestions to aim for around 50 degrees to counter wind resistance. The lightweight nature of the ball may require adjustments in angle compensation, and testing various angles is encouraged. Imparting spin to the ball could enhance distance, but achieving forward spin is complex and may require innovative solutions. It was noted that spinning the ball backward can lead to longer flight distances due to the lift generated by air pressure differences, as explained by the Bernoulli effect. Understanding these principles is crucial for optimizing the catapult's design and performance.
Amenable Me
Messages
4
Reaction score
0
I'm building a catapult meant to fire a plastic ball as far as possible with the following items: 36 popsicle sticks, glue, 6 rubber bands, 4 clothes pins, a small stryofoam cup, and 4 feet of string. The ball has a radius of just under an inch, and it is very light. I am not meant to modify the ball in any way.

I have heard that to counter wind resistance you should aim it at a higher angle, maybe 50 rather than 45. Since it is so light, as in not dense, how much increase in angle should I compensate with?

Also I was wondering if anyone knew a proper, feasible way to make the ball travel a greater distance that won't comprimise the integrity of my catapult. I can upload a diagram of my catapult if necessary.
 
Physics news on Phys.org
Amenable Me said:
I'm building a catapult meant to fire a plastic ball as far as possible with the following items: 36 popsicle sticks, glue, 6 rubber bands, 4 clothes pins, a small stryofoam cup, and 4 feet of string. The ball has a radius of just under an inch, and it is very light. I am not meant to modify the ball in any way.

I have heard that to counter wind resistance you should aim it at a higher angle, maybe 50 rather than 45. Since it is so light, as in not dense, how much increase in angle should I compensate with?

Also I was wondering if anyone knew a proper, feasible way to make the ball travel a greater distance that won't comprimise the integrity of my catapult. I can upload a diagram of my catapult if necessary.

That's what Research and Development is all about. I expect you would try different angles and see which one works best.
When you consider the flight of a table tennis ball which is spinning, you might try to impart some appropriate spin on your ball?
 
PeterO said:
That's what Research and Development is all about. I expect you would try different angles and see which one works best.
When you consider the flight of a table tennis ball which is spinning, you might try to impart some appropriate spin on your ball?
I had considered spin but I can't think of any solutions for that that aren't overly complicated. The problem is that it needs to spin forward, backwards is easy because it does it naturally, but forwards requires some trickyness.
 
Amenable Me said:
I had considered spin but I can't think of any solutions for that that aren't overly complicated. The problem is that it needs to spin forward, backwards is easy because it does it naturally, but forwards requires some trickyness.

Table tennis balls spinning backwards go further! Table tennis balls [and tennis balls] spinning forward dive down - landing short.
 
PeterO said:
Table tennis balls spinning backwards go further! Table tennis balls [and tennis balls] spinning forward dive down - landing short.

Ok, I see my errors in judgement now. After a little research I found out the lift comes from air pressure, not friction with the air. I think it's the Bernouli Affect that says when air is moving faster there is lower pressure. Since the air is freely flowing over the side spinning away from the direction thrown, it should be lifted that way. Thanks for correcting me, otherwise I would have never realized all this.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top