Cauchy-Riemann Equations and Complex Derivatives: A Homework Problem

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Homework Statement



Show that when f(z)=x^3+i(1-y)^3, it is legitimate to write:

f'(z)=u_x+iv_x=3x^2
only when z=i

Homework Equations



Cauchy riemann equations:

u_x=v_y , u_y=-v_x
f'(z)=u_x+i*v_y

The Attempt at a Solution


u=x^3
v=(1-y)^3
u_x=3*x^2
v_y=-3*(1-y)^2
x^2=-(1-y)^2 =

u_y=0
-v_x=0

f'(z)=3*x^2+i(0)= 3*x^2

I don't understand why z=i => z=o+i*1? is relevant to show that f'(z)=3*x^2
 
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f'(z) only has a complex derivative if it satisfies the Cauchy-Riemann equations. You have correctly found that means x^2=-(1-y)^2. How many values of x and y satisfy that?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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