Center of Gravity for nonuniform plank

AI Thread Summary
The discussion centers on determining the center of gravity for a nonuniform plank with a box at one end. The plank is 1.90m long and weighs 23.5kg, while the box has negligible mass and is 75.0 wide. Participants are confused about whether to use the torque equation or the center of gravity formula, especially since the torque is stated to be zero. Clarification is sought on the relationship between the center of gravity and the fulcrum in this context. The conversation emphasizes the need for guidance on applying the principles of torque and center of gravity to solve the problem.
bullsangelsra
Messages
5
Reaction score
0

Homework Statement


A box of negligible mass rests at the left end of a 1.90m, 23.5kg plank The width of the box is 75.0 , and sand is to be distributed uniformly throughout it. The center of gravity of the nonuniform plank is 50.0 from the right end.


I am lost pls help me

i know the torque is going to be zero, but i don't know where to go from here
 
Physics news on Phys.org
is Xcm equal to the fulcrum or the center of gravity?
 
do i use the fact that torque equals zero or do i use the equation for the center of gravity..can someone just point me in the right direction?
 
bullsangelsra said:

Homework Statement


A box of negligible mass rests at the left end of a 1.90m, 23.5kg plank The width of the box is 75.0 , and sand is to be distributed uniformly throughout it. The center of gravity of the nonuniform plank is 50.0 from the right end.
What is the question? Please state the complete problem exactly as it was given.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top