Center of Mass and Moment of Inertia

AI Thread Summary
The discussion focuses on calculating the center of mass and moment of inertia for a system of mass points. The center of mass was determined to be at (13/3 m, 0 m) based on the given masses and their positions. The moment of inertia was calculated using the formula I = mR², resulting in a value of approximately 112.67 kgm². However, the initial answer was found to be incorrect, prompting a request for further assistance. Clarification on the calculations and methodology is sought to resolve the discrepancies.
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Homework Statement



Find the center of mass of the collection of mass points in Figure P.12 and then find the moment of inertia of the system about an axis through the center of mass and parallel to the y-axis.


Homework Equations



Center of Mass
Moment of Inertia

The Attempt at a Solution



M1 = 1kg, r1 = (1i + 0j) m
M2 = 2kg, r2 = (4i + 0j) m
M3 = 3kg, r3 = (6i + 0j) m
Mass total = 6kg

X of CM = 1/6 (0 + 8 + 18) = 13/3 m
Y of CM = 1/6 (0 + 0 + 0) = 0 m

I = mR^{2}
I = 6 (4.333)^{2}
I = 112.6667 kgm^{2}

The answer was wrong. Thanks for the help
 

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