Center of mass: What would make the truck tipover?

AI Thread Summary
The discussion focuses on understanding how the center of mass affects the stability of a truck when adding weight. The user calculates the new center of mass at 1.75 meters from the load's position, which is crucial for determining tipping potential. They explore the relationship between the weight distribution on the axles and the tipping point, emphasizing that if the rear axle's weight exceeds the total weight, the truck will tip over. The user seeks clarification on the moment calculations around the front axle to better understand the tipping dynamics. The conversation highlights the importance of accurately assessing weight distribution to prevent accidents.
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Homework Statement



http://screencast.com/t/ZTk3NDUxNjU

I need help with understanding number 18.


Homework Equations


Center of mase formula: m1x1+m2x2/(all masses)


The Attempt at a Solution


How do you tell if adding the weight will make the truck tipover.

I calculated that the center of mass would shift to 1.75m from where the load was added. Or .25 m from the axle. (axle 1)+(axle 2)/(the whole mass of the system)
2000*4.5+8000*1.5/12000=1.75m from where the new load was added.
 
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Take the moment about the front axle to find resultant weight on the rear axle.

If the rear axle weight is greater than the total weight, then the truck will tip over. Because this will mean that the reaction at the front axle will be downward (like a chain pulling the axle down)
 
hmm I don't quite understand.
would the equation be
x*3/120000=2.5?

This would mean that the distance of the weight of the load would be ignored.
 
Moment about front axle:

Frear axle*3m = Wtruck * 2,5m + Wload * (3m + 1,5m)
 

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