Central Limit Theorem question

murph563
Messages
2
Reaction score
0
Hi i was wondering if you could help me with the following question people?:
The weight of a mint produced by a machine is a random variable with mean 10gm variance 2gm^2.
1. What is the approximate probability that a bag with contents weighing 1000g will have more than 98 but less than 103 mints?
2. find the target weight for the contents so that there will be at least 100 mints in each bag with a probability of 0.99
I don't know what to put for n, and how to go about answering the question help people?
 
Physics news on Phys.org
What have you been able to do with the problem? (Even if you've only identified a formula or theorem that might be useful, and have an idea how it might be useful, that's still something)

And what is this "n" of which you speak?
 
No, the first part of the question says that 100 mints are in a bag and give the probability that the bag will weigh between 980 and 1100 grams, i get that part cos u take n to be 100, but i don't know how ud go about answering these next few parts
 
Okay, here's a start: since you titled this "Central Limit Theorem", the central limit theorem must play some part here. What does the central limit theorem say?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top