Centralizers and elements of odd order

  • Thread starter wakko101
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  • #1
wakko101
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I was going over a proof in which the following is given:

if abb=bba and b is of odd order, then ab=ba (i.e. if b^2 centralizes a then so does b)

I'm not sure why this is so. Any clarification would be appreciated.

Cheers,
W. =)
 

Answers and Replies

  • #2
Dick
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b^2 commutes with a. If b has odd order then b^(2n+1)=e for some n. So b^(2n+1)a=a(b^(2n+1)). Do you see it now?
 
  • #3
wakko101
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I believe so...
b^(2n)ba = ab^(2n)b
b^2n(ba) = b^2n(ab) since abb = bba
ba = ab

If that's it, then cheers! =)
 
  • #4
Dick
Science Advisor
Homework Helper
26,263
620
I believe so...
b^(2n)ba = ab^(2n)b
b^2n(ba) = b^2n(ab) since abb = bba
ba = ab

If that's it, then cheers! =)

Cheers!
 

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