Centre of gravity,centre of charge

  • Thread starter Thread starter Kolahal Bhattacharya
  • Start date Start date
  • Tags Tags
    Charge
AI Thread Summary
The discussion highlights the distinction between the centre of mass and the centre of charge in physics. The centre of mass is significant due to its relationship with inertia and gravity, making it useful for predicting the motion of mass systems. In contrast, charge lacks inertia, and the centre of charge is primarily relevant in cases of symmetrical distribution, such as uniformly charged spheres. When charge distributions are not symmetrical, the geometric centre of charge becomes less useful, necessitating analysis based on the actual charge distribution. The conversation emphasizes that while mass is always positive, charge can be positive or negative, affecting the dominance of terms in calculations involving dipole moments.
Kolahal Bhattacharya
Messages
133
Reaction score
1
In mechanics, we often use centre of centre of mass,but, I have never found anywhere to consider centre of charge even in problems of symmetrical charge distribution.Where is the difference of the two subjects?
 
Physics news on Phys.org
Kolahal Bhattacharya said:
In mechanics, we often use centre of centre of mass,but, I have never found anywhere to consider centre of charge even in problems of symmetrical charge distribution.Where is the difference of the two subjects?
Interesting question.

Mass has two important aspects in physics: inertia and gravity. The centre of mass is useful because mass has the quality of inertia. We don't often care about the gravitational attraction force between two masses as it is so small. The centre of mass of a system of mass is a useful concept in determining how a system of masses will move in response to forces.

Charge has no equivalent to inertia. It is the Coulomb force that we are interested it when it comes to charge. The geometric centre of charge is not particularly useful unless the charge is symetrically distributed about a point (ie a uniformly charged sphere). Then we can treat the sphere as a point charge located at its centre. Otherwise the centre of charge distribution is not particularly useful. We have to analyse the forces based on the actual distribution of charge.

AM
 
Another way of looking at it:

mass (or charge) is the sum of m_i * (r_i)^0 .

the mass center is found by "normalizing" the sum of m_i * (r_i)^1 .
When you do that with charge, you get the dipole moment q_i * r_i .

The big difference is that all masses are positive,
so the mass monopole (r^0) term almost always dominates the situation.

Charges can be positive or negative ...
when the monopole term (Q_total) is zero, it can't dominate ...
so the dipole term (r^1) dominates [over quadrupole, octopole...].
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top