Centripetal Acceleration in Satellites Question

AI Thread Summary
The centripetal acceleration of a satellite in orbit is provided by the gravitational force acting between the satellite and the Earth. This force can be expressed using the formula F_grav = G(M_E m)/r^2, where G is the gravitational constant, M_E is the Earth's mass, m is the satellite's mass, and r is the distance from the Earth's center to the satellite. According to Newton's Second Law, this gravitational force equals the mass of the satellite multiplied by its centripetal acceleration, which can be expressed as a_c = v^2/r. By equating these two expressions, one can derive the speed of the satellite in orbit. Understanding this relationship clarifies how gravitational force is essential for maintaining a satellite's circular motion.
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Homework Statement



What provides the force that causes the centripetal acceleration of a satellite in orbit?


2. The attempt at a solution

I'm really confused about the answer to this question because in class my teacher only taught us how to solve satellite problems if we are given the distance and we have to find speed http://img85.imageshack.us/img85/2097/physicshw7.png .[/URL]
Can someone please help me.. or just explain what i would need to know to get the answer to this problem! thanks sooo much!
 
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The force that provides the centripetal acceleration for a satellite orbiting in uniform circular motion (that is, the satellite has the same speed at every point on its orbit) is the gravitational force:

F_{grav} = G \frac{M_Em}{r^2}

Where G is the gravitational constant (this is easy to find, its probably in the cover of your textbook), ME is the mass of the earth, m is the mass of the satellite, and r is the distance between the center of the Earth and the satellite.

You know by Newton's Second Law that this gravitational force must equal the mass of the satellite times the centripetal acceleration, and the centripetal acceleration in terms of speed is:

a_c = \frac{v^2}{r}

And so we have:

G \frac{M_Em}{r^2} = m \frac{v^2}{r}

And now you can solve for the speed. Does that help?
 
yes! thank you so much :)
 
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