Centripetal Force: Calculating Tension in Conical Pendulum

AI Thread Summary
To calculate the tension in a conical pendulum with a string length of 1.2 m and a bob mass of 0.41 kg at a 21° angle, the relationship T = mlω² can be used. It is suggested to first draw a diagram to visualize the forces acting on the pendulum. The tension can be derived from the equation Tcos(θ) = mg, leading to a calculated tension of 4.30 N. Understanding the components of tension and gravitational force is key to solving the problem. This approach effectively determines the tension in the string of a conical pendulum.
kingyof2thejring
Messages
82
Reaction score
0
Question 1
A conical pendulum consists of a string of length 1.2 m and a bob of mass 0.41 kg. The string makes an angle of 21° with the vertical. Calculate the tension in the string, in N.
iam not sure wat to do here if
l\omega{}^2 = \frac{g}{\cos\phi}
then i use
T=ml\omega{}^2 to get the force. is that the way to calculate the tension. Thanks in advance
 
Last edited:
Physics news on Phys.org
kingyof2thejring said:
Question 1
A conical pendulum consists of a string of length 1.2 m and a bob of mass 0.41 kg. The string makes an angle of 21° with the vertical. Calculate the tension in the string, in N.
iam not sure wat to do here if
l\omega{}^2 = \frac{g}{\cos\phi}
then i use
T=ml\omega{}^2 to get the force. is that the way to calculate the tension. Thanks in advance
First draw a diagram. I think you will see the answer when you do that.

(what would the tension be if it were straight down?)
 
Tcos 0 = mg
T=4.30
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top