Centripetal Force Homework: Solving for F with F = ma

AI Thread Summary
The discussion revolves around calculating centripetal force using the formula F = (mass)(angular speed squared)(average radius). The initial calculations yielded excessively large values, prompting a review of unit conversions from grams to kilograms and revolutions per second to radians per second. After converting units correctly, the calculated force was approximately 896.2 N, which raised concerns about its reasonableness for a classroom experiment. A participant noted a miscalculation that adjusted the final value to 890.62 N. The conversation emphasizes the importance of accurate unit conversions and understanding angular speed in centripetal force calculations.
jensson
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Homework Statement


I did an expirement in my physics lab on centripetal force. I'm doing the calculations and right now I am calculating the centripetal force using equation: F= (mass)(angular speed squared)(average radius). My answers are coming out to be huge numbers.

ex: (148.8g)(52.70 rev/s)^2(5.494 cm) = 2270217

I'm not even sure what units this converts too.

If I convert g to kilegrams and revolutions/second times 2pi (in radians) then convert cm to meters I get:

(0.1488 kg) (331^2)(0.05494 m ) = 895.7 N

but this is too big as well. what am I doing wrong??
 
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You need the angular speed in the formula. How is it defined? ehild
 
the equation for angular speed we're using is 2pi (n)/elapsed time

n is revolutions

I think I need to convert this to m/s?
 
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is 896.2 N reasonable?
 
jensson said:
is 896.2 N reasonable?

almost... It is 890.62 N. One zero is missing.

ehild
 
can you please show me how you got that? because when I put

(0.1488) (331.1^2) (0.05494) that comes out to 896.2 N
 
You are right, I misread something on my calculator.

ehild
 
that seems like a lot of Newtons! This was an experiment in class with a little motor driven rotator.
 
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