Centripetal Force Homework: Total Energy, Speed, Tension & Distance

In summary, the problem involves a 0.10 kilogram solid rubber ball attached to an 0.8 meter length of light thread and swinging in a vertical circle with point P at 0.20 meter above the floor. The ball has a speed of 6.0 meters per second at the top of the circle and the total energy is constant. To solve the problem, we can use the equations PE + KE = TE and a = v^2/r, taking into account the acceleration towards the center by the forces involved. The tension of the thread can be determined at the top and bottom of the circle, and the horizontal distance the ball travels before hitting the floor can be calculated.
  • #1
sobek
15
0

Homework Statement


A 0.10 kilogram solid rubber ball is attached to the end of an 0.0 meter length of light thread. The ball is swung in a vertical circle. point P, the lowest point of the circle, is 0.20 meter above the floor. The speed of the ball at the top of the circle is 6.0 meters per second, and the total energy is kept constant.
a)Determine the total energy of the ball, using the floor as the zero point for gravitational potential energy.

b)Determine the speed of the ball at point P, the lowest point of the circle

c)Determine the tension of the thread at...
i. the top of the circle
ii. the bottom of the circle

The ball only reaches the top of the circle once before the thread breaks when the bal is at the lowest point of the circle.
d)Determine the horizontal distance that the ball travels before hitting the floor


Homework Equations



PE + KE =TE
a= m*v^2/r

The Attempt at a Solution



for part a, i know I am supposed to use PE + KE = TE, but for "h" in PE, what's the height? Is it 1.8 meters?

and then I'm not sure how to set up the rest of the parts.
Any tips on how to set up the problem are appreciated.
thanks
 
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  • #2
Length 0.0m?
You need to combine the two eqns. you wrote by taking into account the acceleration towards center by the forces involved. Then eliminate v to get T.
 
  • #3
sorry length is 0.8meters
 

Frequently Asked Questions about Centripetal Force Homework

What is the difference between centripetal force and centrifugal force?

Centripetal force is the force that keeps an object moving in a circular path, while centrifugal force is the apparent outward force that appears to act on an object moving in a circular path. Centripetal force is a real force, while centrifugal force is a fictitious force.

How can I calculate the total energy of an object moving in a circular path?

The total energy of an object moving in a circular path is equal to the sum of its kinetic energy and potential energy. The kinetic energy can be calculated using the formula KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity. The potential energy can be calculated using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height of the object above the ground.

What is the relationship between speed and centripetal force?

The centripetal force required to keep an object moving in a circular path is directly proportional to the speed of the object. This means that as the speed increases, the centripetal force required also increases.

How does tension affect an object moving in a circular path?

Tension is the force that acts on an object when it is being pulled or stretched. In the case of an object moving in a circular path, tension acts as the centripetal force that keeps the object in its circular motion. The magnitude of tension required depends on the mass, speed, and radius of the circular path.

What is the relationship between distance and centripetal force?

The centripetal force required to keep an object moving in a circular path is inversely proportional to the distance between the object and the center of the circle. This means that as the distance increases, the centripetal force required decreases. This relationship is described by the equation Fc = m * v^2 / r, where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius of the circular path.

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