Centripetal Force (Loop the Loop)

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SUMMARY

The discussion focuses on calculating the apparent weight experienced by a pilot during a loop-the-loop maneuver in a jet. Given the pilot's mass of 78.0 kg, a constant speed of 105 m/s, and a loop radius of 0.562 km, the formula used is F = m(V^2/R). The calculated force at the bottom of the loop is 1530.2 N, which represents the force exerted by the pilot against the seat due to centripetal acceleration.

PREREQUISITES
  • Understanding of centripetal force and acceleration
  • Familiarity with Newton's second law of motion
  • Knowledge of basic physics equations involving mass, velocity, and radius
  • Ability to perform unit conversions (e.g., km to meters)
NEXT STEPS
  • Study the effects of centripetal acceleration on different masses
  • Learn about the implications of speed changes on apparent weight in circular motion
  • Explore real-world applications of centripetal force in aviation
  • Investigate the physics of other maneuvers in jet flight
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Aerospace engineers, physics students, pilots, and anyone interested in the dynamics of circular motion and its effects on human occupants in high-speed environments.

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Homework Statement


A pilot, whose mass is 78.0 kg, makes a loop-the-loop in a fast jet. Assume that the jet maintains a constant speed of 105 m/s and that the radius of the loop-the-loop is 0.562 km. What is the apparent weight that the pilot feels (i.e., the force with which the pilot presses against the seat) at the bottom of the loop-the-loop?


Homework Equations


F = m(V^2/R)


The Attempt at a Solution



F = 78 (105^2/562)
F = 1530.2 N
 
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nevermind
n = m(g + v^2/R)
 

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