Centripetal Force Minimum Period Question

AI Thread Summary
A boy spins a 3.00 kg rock tied to a 0.70 m string, with the string breaking at a tension greater than 80.0 N. To find the minimum period for the rock's circular motion, the relevant equation is T = 2π√(r/g), which relates tension, mass, radius, and period. The calculations yield a minimum period of approximately 1.02 seconds, though slight variations in results are noted. The relationship between maximum tension and minimum period is explained by the need for maximum speed to cover the circular distance in the shortest time. Understanding this connection clarifies the dynamics of centripetal force in circular motion.
Lax0
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Homework Statement


A boy ties a 3.00kg rock to a 0.70 m string and begins spinning it around in a horizontal circle at a constant speed. If the string will break if the tension is greater than 80.0 N, what is the minimum period for the rock to spinning in a circle. How do i solve this?


Homework Equations



m4∏^(2 ) r/T^2

The Attempt at a Solution


80.0= (3.00)4∏^(2)(0.70)/T^2
T= 1.02
 
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Looks good. I get a very slightly larger answer; might be worth running it through the calculator again.
 
Your equations written as pie squared r instead of pie r squared, i think you did it right but it looks weird
 
anaximenes said:
Your equations written as pie squared r instead of pie r squared, i think you did it right but it looks weird

its the equation in the textbook. So can you explain how max tension gets minimum period?
 
Lax0 said:
its the equation in the textbook.
Yes, the equation is correct, though it does look odd at first sight.
So can you explain how max tension gets minimum period?
The stone has a certain distance to cover, 2πr, in one period. So minimum period means maximum speed, and that means maximum tension.
 
Sorry your right, its so weird seeing pie digitally
 
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