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Homework Help: Centripetal Motion of Charges

  1. Sep 2, 2011 #1
    A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.694 g, q = 5.04 µC is located on the x axis at x = 20.2 cm, moving with a speed of 34.0 m/s in the positive y direction. For what value of Q (in μC) will the moving particle execute circular motion? (Neglect the gravitational force on the particle.)

    I tried plugging everything in, I just can't seem to figure out where to put the mass or velocity, if at all needed.

    does F=k(.00504C)(Q)/(.202^2) ?

    I really need somewhere to start
  2. jcsd
  3. Sep 2, 2011 #2

    Doc Al

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    Staff: Mentor

    What must the acceleration be, if it's to execute circular motion? Apply Newton's 2nd law.

    Note that µC means micro C = 10-6 C.
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