A Chain Rule in Lagrangian Transformation

AI Thread Summary
The discussion centers on demonstrating the invariance of the Lagrangian under coordinate transformations as outlined in Goldstein's textbook. A participant seeks clarification on the origin of the term ∂q_i/∂t in the expression for the time derivative of q_i, which is resolved through the application of the chain rule. It is noted that the term involving ∂q/∂dot s can be disregarded since q is independent of dot s. Additionally, the conversation shifts towards the advantages of using the Hamiltonian formulation over the Lagrangian approach, highlighting its utility in revealing the symplectic structure of phase space and its connections to quantum theory. The discussion emphasizes the importance of understanding these transformations in classical mechanics.
SEGFAULT1119
Messages
4
Reaction score
0
Hello,
I'm trying to follow Goldstein textbook to show that the Lagrangian is invariant under coordinate transformation. I got confused by the step below
So
## L = L(q_{i}(s_{j},\dot s_{j},t),\dot q_{i}(s_{j},\dot s_{j},t),t)##

The book shows that ##\dot q_{i} = \frac {\partial q_{i}}{\partial s_{j}} \dot s_{j} + \frac{\partial q_{i}}{\partial t} ##,and I'm not sure where the ##\frac{\partial q_{i}}{\partial t} ## term come from? I've tried to look up chain rules for coordinate transformation but I can't find anything.

Please help!

Thank you :D
 
Physics news on Phys.org
It is just the standard chain rule. Consider a function ##f(h,g)## where ##h## and ##g## are functions of some parameter ##t## and differentiate ##f## with respect to ##t##. The chain rule now states
$$
\frac{df}{dt} = \frac{\partial f}{\partial h} \frac{dh}{dt} + \frac{\partial f}{\partial g} \frac{dg}{dt}.
$$
Now, if ##g = t## you would obtain ##dg/dt = dt/dt = 1## and ##\partial f/\partial g = \partial f/\partial t## and therefore
$$
\frac{df}{dt} = \frac{\partial f}{\partial h} \frac{dh}{dt} + \frac{\partial f}{\partial t}.
$$

What is unclear is why a term ##(\partial q/\partial \dot s) \ddot s## is not included. You can only ignore this term if ##q## is a function only of ##s## and not of ##\dot s##.
 
  • Like
Likes SEGFAULT1119
@Oroduin,

You are correct. q is independent of ##\dot s##. I mistyped the question. And thank you for your answer.
 
If you want more general transformations, it's better to use the generalized Hamilton principle in terms of the Hamiltonian rather the Lagrangian formulation. This leads to the more general canonical transformations in phase space rather than the less general diffeomorphism invariance of the Lagrangian formalism in configuration space.

The Hamiltonian phase-space formalism turns out to be the most valuable form of classical mechanics from a fundamental-physics point of view since it reveals the symplectic structure of phase space and allows for a quasi algebraic formulation of the dynamics in terms of Poisson brackets, which brings the classical theory very close to its extension to quantum theory.
 
Thread 'Gauss' law seems to imply instantaneous electric field propagation'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Thread 'Griffith, Electrodynamics, 4th Edition, Example 4.8. (First part)'
I am reading the Griffith, Electrodynamics book, 4th edition, Example 4.8 and stuck at some statements. It's little bit confused. > Example 4.8. Suppose the entire region below the plane ##z=0## in Fig. 4.28 is filled with uniform linear dielectric material of susceptibility ##\chi_e##. Calculate the force on a point charge ##q## situated a distance ##d## above the origin. Solution : The surface bound charge on the ##xy## plane is of opposite sign to ##q##, so the force will be...
Back
Top