Chair leg pressure problem geez

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SUMMARY

The discussion focuses on calculating the pressure exerted on the floor by each leg of a chair when a 63 kg person sits on a 3.5 kg chair. The total weight is 66.5 kg, and with each leg having a contact area of 0.00011304 m², the pressure is calculated using the formula P = F/A. The correct pressure exerted by each leg is 1.44E6 Pa, confirming that the initial calculation was accurate despite the confusion in the presentation of the answer.

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Chair leg pressure problem...geez

Homework Statement



A 63kg person sitting on 3.5kg chair. Four legs contact the floor, each leg with circle 1.2cm in diameter. Find pressure exerted on floor by each leg of chair (weight evenly distributed).


Homework Equations



[{(person mass) + (chair mass)} * (9.81)] / pi (radius contact circle in meters)(4 chair legs)

The Attempt at a Solution



63kg + 3.5kg = 66.5kg total

1.2cm diameter = 0.6cm radius = 0.006m radius

area = 0.00011304 m^2 each leg
area total four chair legs = 0.00045216 m^2

P = F/A

{(66.5)(9.81)} / 0.00045216 = 1442774.68 N/m^2

...thus for one leg = 360693.67 N/m^2

answer of 3.6E5 and 3.61E5 incorrect.

Answer unit requested is Pa.

What am I missing here?
 
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The pressure is the same for all four legs. You shouldn't have divided by 4.

Pressure (on each/all chair leg(s)) = (total force) / (total area) = (partial force) / (partial area)
 
Goofy err on my part. Actually had the answer correct the first time with 1442774.68 but posted my answer as 1.4E6...the correct way to post my answer was 1.44E6

Thank you
 

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