Change in Classical Velocity of an Electron

merlinh
Messages
1
Reaction score
0

Homework Statement


Copper nucleus at origin and an electron initially 2 A away from origin. Electron moved to 1A away from origin. What is the change in classical velocity of the electron?


Homework Equations


PE= (kq1q2)/r
change in PE from distance of 2A = KE



The Attempt at a Solution


change in PE from distance of 2A = KE
KE = 1/2mv^2
Change in PE =PE2-PE1=1/1-1/2= 1-1/2=1/2 J
KE=1/2m(v2-v1)^2=1/2 J
and solve for v2-v1?
I don't think I am understanding this right.
 
Physics news on Phys.org
merlinh said:

Homework Statement


Copper nucleus at origin and an electron initially 2 A away from origin. Electron moved to 1A away from origin. What is the change in classical velocity of the electron?


Homework Equations


PE= (kq1q2)/r
change in PE from distance of 2A = KE



The Attempt at a Solution


change in PE from distance of 2A = KE
KE = 1/2mv^2
Change in PE =PE2-PE1=1/1-1/2= 1-1/2=1/2 J
KE=1/2m(v2-v1)^2=1/2 J
and solve for v2-v1?
I don't think I am understanding this right.
I assume that the electron is orbiting the nucleus, you can use a certain equation to find the force on the electron, and you know how many protons copper nucleus has. use this to find the velocites.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top