Change in number of microstates

Kara386
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Homework Statement


An isolated macroscopic system at 300K absorbs a photon with ##\lambda = 550nm##. What is the relative increase ##\frac{\Delta \Omega}{\Omega}## in microstates.

Homework Equations

The Attempt at a Solution


The energy of the photon is ##E = \frac{hc}{\lambda}## so that would be the change in internal energy. And ##dU = TdS - pdV## but I assume ##dV = 0## so ##dU = TdS##.

##S = k \ln(\Omega)## so I think ##dS = k d\ln(\Omega)##:

##d \ln(\Omega) = \frac{hc}{\lambda T}##
If that's all ok, I don't know how to get from there to ##\Delta \Omega## or how to get the relative increase in ##\Omega##! Thanks for any help!
 
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Kara386 said:
##d \ln(\Omega) = \frac{hc}{\lambda T}##
...I don't know how to get from there to ##\Delta \Omega## or how to get the relative increase in ##\Omega##! Thanks for any help!
You just need to carry out the differential of ##\ln \Omega##. You don't need to find ##\Delta \Omega##, you only need ##\frac{\Delta \Omega}{\Omega}##.
https://en.wikipedia.org/wiki/Differential_of_a_function
 
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TSny said:
You just need to carry out the differential of ##\ln \Omega##. You don't need to find ##\Delta \Omega##, you only need ##\frac{\Delta \Omega}{\Omega}##.
https://en.wikipedia.org/wiki/Differential_of_a_function
Thank you for that link! Been trying to find out what it's called when you put a 'd' in front of variables for ages. And how to then actually do something with it. Thanks for your help!
 

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