Change in Potential Energy: What am I doing wrong?

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SUMMARY

The discussion centers on calculating the change in potential energy for a block moving up an inclined plane. The block, weighing 4.20 kg and initially moving at 7.70 m/s, comes to rest after traveling 3.00 m on a 30.0° incline. The user incorrectly calculated the potential energy change as 56.1 J due to using the sine of 30 degrees in grads instead of degrees. The correct approach involves using the formula DeltaU = mg(3.00)sin(30°), where the sine of 30° is 0.5, leading to a correct potential energy change of 61.2 J.

PREREQUISITES
  • Understanding of basic physics concepts such as kinetic and potential energy.
  • Familiarity with trigonometric functions, specifically sine values.
  • Knowledge of the formula for gravitational potential energy change: DeltaU = mg(h).
  • Ability to use a scientific calculator and check its mode settings (degrees vs. grads).
NEXT STEPS
  • Review the principles of energy conservation in physics.
  • Learn about the effects of incline angles on potential energy calculations.
  • Practice using trigonometric functions in different calculator modes.
  • Explore more complex problems involving inclined planes and energy transformations.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone seeking to understand energy transformations in mechanics, particularly in scenarios involving inclined planes.

Fittleroni
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Homework Statement


A 4.20 kg block is set into motion up an inclined plane with an initial speed of v0 = 7.70 m/s (Fig. P7.25). The block comes to rest after traveling 3.00 m along the plane, which is inclined at an angle of 30.0° to the horizontal.

1. For this motion, determine the change in the block's kinetic energy.
DeltaK = 1/2m(vf^2-vi^2)^2=-1/2mvi^2= -124.5J

This next question is the portion I am having problems with:

2. For this motion, determine the change in potential energy of the block-Earth system.

Homework Equations



DeltaU = mg(3.00)sin30.0

The Attempt at a Solution



=(4.20)(9.8)(3.00)(0.454)
=56.1

So what is wrong with my answer??
 
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What's the sine of 30 degrees?
 
Fittleroni said:

Homework Equations



DeltaU = mg(3.00)sin30.0

The Attempt at a Solution



=(4.20)(9.8)(3.00)(0.454)
=56.1

So what is wrong with my answer??

Before you begin calculations involving trig functions, always check the mode your calculator has been left in. The sine of 30 grads is 0.454; you need to reset the input mode to degrees...
 

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