Change in Potential Energy: What am I doing wrong?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 4K views
Fittleroni
Messages
22
Reaction score
0

Homework Statement


A 4.20 kg block is set into motion up an inclined plane with an initial speed of v0 = 7.70 m/s (Fig. P7.25). The block comes to rest after traveling 3.00 m along the plane, which is inclined at an angle of 30.0° to the horizontal.

1. For this motion, determine the change in the block's kinetic energy.
DeltaK = 1/2m(vf^2-vi^2)^2=-1/2mvi^2= -124.5J

This next question is the portion I am having problems with:

2. For this motion, determine the change in potential energy of the block-Earth system.

Homework Equations



DeltaU = mg(3.00)sin30.0

The Attempt at a Solution



=(4.20)(9.8)(3.00)(0.454)
=56.1

So what is wrong with my answer??
 
Physics news on Phys.org
Fittleroni said:

Homework Equations



DeltaU = mg(3.00)sin30.0

The Attempt at a Solution



=(4.20)(9.8)(3.00)(0.454)
=56.1

So what is wrong with my answer??

Before you begin calculations involving trig functions, always check the mode your calculator has been left in. The sine of 30 grads is 0.454; you need to reset the input mode to degrees...