Change in radius over time for a spherical ball formula

AI Thread Summary
The discussion focuses on the correct application of algebra in deriving the change in radius over time for a spherical ball. The volume formula is clarified as v = (4/3)πr^3, leading to the differentiation dv/dt = 4πr^2(dr/dt). Participants are prompted to apply the ideal gas law, pv = (rG)v = NkT, and use the product rule for differentiation. The conversation emphasizes substituting v and dv/dt in the derived equations to achieve accurate results. Overall, the thread seeks clarity on the algebraic manipulations involved in the calculations.
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Homework Statement
https://www.asi.edu.au/wp-content/uploads/2015/08/NQE_2008_Physics.pdf
Pg 7
Q 12 E)
Relevant Equations
v^r = c dT/dt
P = rG
PV = NkT
1598193191413.png

Algebra in this answer does not seem to flow right. Firstly, the 16, secondly the n term.
Can someone explain or show me the right answer?
 
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Since big ##V## is used for voltage, denote the volume with little ##v##. You know ##v = \frac{4}{3}\pi r^3##, so $$\frac{dv}{dt} = 4\pi r^2 \frac{dr}{dt}$$Now you will require the ideal gas law,$$pv = (rG)v = NkT$$ Use the product rule when differentiating both sides w.r.t. ##t##,$$Gr\frac{dv}{dt} + Gv\frac{dr}{dt} = Nk \frac{dT}{dt}$$What do you get if you replace ##v## with ##\frac{4}{3}\pi r^3##, and also replace ##\frac{dv}{dt}## with ##4\pi r^2 \frac{dr}{dt}##? Also, it is helpful to note that ##N = nN_A##.
 
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