Characteristic Polynomial for A with a=-1

[keddelove]

And again a question:

L is a field for which a \in L. The matrix

<br /> A = \frac{1}{2}\left( {\begin{array}{*{20}c}<br /> 1 &amp; 1 &amp; 1 &amp; 1 \\<br /> 1 &amp; a &amp; { - 1} &amp; { - a} \\<br /> 1 &amp; { - 1} &amp; 1 &amp; { - 1} \\<br /> 1 &amp; { - a} &amp; { - 1} &amp; a \\<br /> \end{array}} \right)<br />

has the characteristic polynomial

<br /> x^4 - \left( {a + 1} \right)x^3 + \left( {a - 1} \right)x^2 + \left( {a + 1} \right)x - a<br />

I need to show that this information is correct for a=1 in any field.

My problem is that when i calculate the polynomial for a=-1 I end up with another characteristic polynomial than the one given. Maybe I'm going about it the wrong way. Suggestions or pointers are very welcome

 

[Hurkyl]

I don't understand the question...

And if you want to show something is correct for a=1, then why are you looking at a=-1?

 

[mathwonk]

i conjecture he meant the characteristic polynomial is accurate for a any element of any field, and yet it failed for a = -1.

 

[keddelove]

Oops, should have stated:

Show that this is correct for a=-1 in any field.