Characteristic polynomial of a matrix

ptolema
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Homework Statement



Let A be an nxn matrix with real number entries, in which all entries are 1. Find the characteristic polynomial of A.

Homework Equations



characteristic polynomial: f(t)=det(A-tI), I is identity matrix
matrix.jpg


The Attempt at a Solution


I've tried to do this by various methods of induction, only to encounter massive blocks along the way. I can't really do anything with this past plug in numbers and hope something works. I know the equation should be (-1)ntn-1(t-n), but I don't know how to prove it. This is from a section of my book on invariant subspaces, is there anything I could do with those?
 
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I have a suggestion, though it may be misguided. Try finding the null space and image of A. The vectors that span the null space are eigenvectors with eigenvalue 0. From the image, you should be able to identify the remaining eigenvector and its eigenvalue. From that, you can deduce everything except the factor of (-1)n.
 
Well, one way to do it is to use the formula for determinant

<br /> det A = \epsilon_{i_1i_2...i_N}A_{i_11}A_{i_22}...A_{i_NN}<br />

For your case A_{ij} = 1 - t\delta_{ij}

Also useful, will be the fact

\sum\limits_{i=1}^N\sum\limits_{j=1}^N \epsilon_{ijklm...} = 0
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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