Charge on the surface of a conducting sphere.

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SUMMARY

The discussion focuses on calculating the charge and surface charge density on a conducting sphere with a radius of 0.15 meters and a potential of 200 volts. The formula for the potential of a spherical conductor, V = (1/4πε₀) * Q/R, is utilized to derive the charge (Q). By rearranging the formula, Q is determined to be 0.00075 coulombs. Subsequently, the surface charge density is calculated using the formula σ = Q/A, where the surface area A is 0.28274 m², resulting in a surface charge density of approximately 2.65 C/m².

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with the concept of electric potential
  • Knowledge of surface charge density calculations
  • Basic proficiency in geometry for calculating surface area
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  • Learn about Gauss's Law and its applications in electrostatics
  • Explore the effects of charge distribution on electric fields
  • Investigate the relationship between charge density and electric potential in conductors
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Students and professionals in physics, electrical engineering, and anyone interested in understanding electrostatic principles and calculations related to conducting spheres.

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I need to find the charge and charge density on the surface of a conducting sphere of radius r=0.15m and of a potential of V=200V.

I know the surface charge density, which is Q/A. The surface area is 0.28274, but I can't find the charge.
 
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Potential of a spherical conductor is
V = (1/4πεο)*Q/R.
Find Q, then surface charge density.
 

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