Charges near a conducting plane

AI Thread Summary
The discussion focuses on the configuration of charges and conducting planes, specifically analyzing a square arrangement of charges and the resulting equipotential surfaces. It is noted that the method of image charges can effectively solve cases with conducting planes at 90 degrees, but challenges arise with configurations like a point charge on the bisector of a 120° dihedral angle. Participants agree that introducing image charges becomes problematic in this scenario, as it complicates maintaining constant potential at the planes. The conversation also hints at the possibility of other angles being solvable, though specifics are not provided. Overall, the thread emphasizes the limitations and considerations of using image charges in various geometrical setups.
JSGandora
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Homework Statement


Locate two charges q each and two charges –q each on the corners of a square, with like charges diagonally opposite on another. Show that there are two equipotential surfaces that are planes. In this way obtain, and sketch qualitatively, the field of a single point charge located symmetrically in the inside corner formed by being a metal sheet through a right angle. Which configurations of conducting planes and point charges can be solved this way and which can’t? How about a point charge located on the bisector of a 120° dihedral angle between two conducting planes?

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The Attempt at a Solution



I understand this is an extension of the method of image charges and I think that only conducting planes at 90° to each other can be solved in this way. For the 120° case, the image charges lie on the plane of the two conducting planes and there is no good way to introduce another image charge so that the potential at the planes is constant. Is this correct?
 
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JSGandora said:
For the 120° case, the image charges lie on the plane of the two conducting planes and there is no good way to introduce another image charge so that the potential at the planes is constant.
That looks right to me.
JSGandora said:
I think that only conducting planes at 90° to each other can be solved in this way.
No, I believe there are other angles. Which ones won't have the problem you mentioned in respect of 120 degrees?
 
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