Charges placed in right triangle pls HELP

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SUMMARY

The discussion focuses on calculating the electric field strength at point "A," located at the midpoint of the hypotenuse of a right triangle formed by three charges (q1, q2, q3). The relevant equation for electric field strength is E = kq/r², where k is Coulomb's constant. The participant correctly identifies that the midpoint is equidistant from the three charges and suggests finding the resultant electric fields from the two charges at the ends of the hypotenuse before incorporating the third charge's field. This approach leads to determining both the magnitude and direction of the total electric field at point "A."

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Basic knowledge of right triangle geometry
  • Familiarity with vector addition of forces
  • Ability to calculate angles and distances in a triangle
NEXT STEPS
  • Study the application of Coulomb's Law in electric field calculations
  • Learn about vector addition techniques for resultant forces
  • Explore the concept of electric field lines and their representation
  • Investigate the effects of multiple charges on electric fields
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sunny.heyar
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Homework Statement


Charges q1, q2, q3 are placed in a right triangle.
Charges are given, distance between charges is given.
Find the electrical field strength at point "A" which is in the middle of the hypotenuse.
Which equations and how would I figure that out knowing that I have to give magnitude and direction?

Homework Equations


E=kq/r^2 --> ?not sure


The Attempt at a Solution


I drew out a diagram and found all the angle, after that I am completely lost.
 
Physics news on Phys.org
In a right angled triangle, mid point of the hypotenuse is equidistant from three vertexes.
At A, two fields are in the opposite direction due to two charges at the ends of the hypotenuse. Find the resultant of these two. You can find the angle between the resultant of the two field and third field,and resultant of all the three fields.
 

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