Charges placed in right triangle pls HELP

In summary, to find the electrical field strength at point A in a right triangle with charges q1, q2, and q3, you can use the equation E=kq/r^2 and calculate the resultant of the two fields in opposite directions due to charges at the ends of the hypotenuse. You can then find the angle between this resultant and the third field to determine the magnitude and direction of the electrical field at point A.
  • #1
sunny.heyar
1
0

Homework Statement


Charges q1, q2, q3 are placed in a right triangle.
Charges are given, distance between charges is given.
Find the electrical field strength at point "A" which is in the middle of the hypotenuse.
Which equations and how would I figure that out knowing that I have to give magnitude and direction?

Homework Equations


E=kq/r^2 --> ?not sure


The Attempt at a Solution


I drew out a diagram and found all the angle, after that I am completely lost.
 
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  • #2
In a right angled triangle, mid point of the hypotenuse is equidistant from three vertexes.
At A, two fields are in the opposite direction due to two charges at the ends of the hypotenuse. Find the resultant of these two. You can find the angle between the resultant of the two field and third field,and resultant of all the three fields.
 
  • #3


I would approach this problem by using the equation E=kq/r^2, where E is the electric field strength, k is the Coulomb's constant, q is the charge, and r is the distance between the charges. In this case, we have three charges placed in a right triangle, so we can use the Pythagorean theorem to find the distance between the two charges on the hypotenuse.

Once we have the distance, we can plug in the values for the charges and the distance into the equation to find the electric field strength at point A. However, since there are three charges, we need to take into account the direction of the electric field. To do this, we can use vector addition to find the net electric field at point A.

Another approach would be to use the concept of superposition, where we can find the electric field at point A by considering the individual electric fields produced by each charge and adding them together. This would involve using the equation E=kq/r^2 for each charge and then using vector addition to find the net electric field at point A.

Overall, the key equations to use in this problem would be the equation for electric field strength and the Pythagorean theorem. Additionally, it is important to consider the direction of the electric field and use vector addition or the principle of superposition to find the net electric field at point A.
 

1. What is a right triangle?

A right triangle is a type of triangle where one of the angles measures 90 degrees. It is also known as a right-angled triangle.

2. How are charges placed in a right triangle?

Charges can be placed in a right triangle by assigning each side of the triangle with a positive or negative value. The corner where the two sides meet will have a resultant charge based on the values of the two sides.

3. Why is a right triangle commonly used in physics experiments?

A right triangle is commonly used in physics experiments because it is a simple and symmetrical shape that allows for easier calculation of the forces and charges involved. It also follows the Pythagorean theorem, which relates the sides of a right triangle to each other.

4. How does the placement of charges in a right triangle affect the overall electric field?

The placement of charges in a right triangle affects the overall electric field by creating a net charge at the corner where the two sides meet. The strength and direction of the electric field at any point within the triangle will depend on the values and placement of the charges.

5. Can charges be placed in a right triangle in a way that cancels out the electric field?

Yes, it is possible to place charges in a right triangle in a way that cancels out the electric field. This can be achieved by placing equal but opposite charges on the two sides that meet at the right angle. The net charge at the corner will then be zero, resulting in a zero electric field within the triangle.

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