1. The problem statement, all variables and given/known data Switch is initially opened with the capacitor uncharged. At t=0 the switch is clsoed. At time=t1 later, the potential difference between A and B is 2.00volts Find the charge on the capacitor at time t1. R=10,000ohms C=2.4nF Vb=12volts VA->B-=2.00volts 2. Relevant equations I(t)=(V/R)*e^(-t/RC) q(t)=CV(1-e^(-t/RC)) C=Q/V 3. The attempt at a solution RC was correctly found to be 40microSeconds.So then the goal is to find the time at t1. The 2volts across A and B must be important to finding t1. So I assumed that the voltage drop from A-B must be equal to the voltage drop for R3. Thus 2Volt/R=I3. Then I used I3 to find t1: I3=(V/R)*e^(-t/RC) --> solving for t and then plugging into q(t). Does this seem right or is my logic wrong?