(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 4.63mF capacitor has stored energy to heat 3.00kf of water from 22 degrees C to 94.5 degrees C. What the potential difference?

2. Relevant equations

Q= mC delta T

W= Q sq/2C

V=W/C

3. The attempt at a solution

Q= mC delta T

Q= 3kg* 4.184* ( 94.5-22) = 910.02 J

then 910.02 sq/ 2* 4.63X -6= 8.94E 10

8.94e10 / 910.02= 9.82e7

is that right my teacher said it wrong

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# Homework Help: Check Potential Difference

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