Checking Vectors Homework: Acceleration to Distance

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A bicyclist with a uniform acceleration of 2.30 m/s² aims to reach a velocity of 21 m/s from rest. The correct formula to use is v² = u² + 2as, where u is the initial velocity, which should be 0 in this case. The initial calculation of 94.72 m is incorrect due to misidentifying the initial velocity; it should not be set to 2.30 m/s². The correct approach involves recognizing that the initial velocity (u) is 0, leading to a different distance calculation. Understanding the variables in the formulas is crucial for accurate problem-solving in physics.
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Homework Statement


I've done this problem please check.
A bicyclist has a uniform acceleration of 2.30ms-2. What distance will he need to travel in order to attain a velocity of 21ms-2 if he started at rest?


Homework Equations


Hopefully this is the equation:
v2=u2+2as
i have rearranged this in my problem.

The Attempt at a Solution


v2-u2/2a
212-2.302/2*2.30
=94.72m

Please check the working and the final measrement (94.72m)
thanks
 
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Awsom Guy said:

Homework Statement


I've done this problem please check.
A bicyclist has a uniform acceleration of 2.30ms-2. What distance will he need to travel in order to attain a velocity of 21ms-2 if he started at rest?

Homework Equations


Hopefully this is the equation:
v2=u2+2as
i have rearranged this in my problem.

The Attempt at a Solution


v2-u2/2a
212-2.302/2*2.30
=94.72m

Please check the working and the final measrement (94.72m)
thanks

v = v_0 + a*t, and
x = x_0 + v_0*t + .5*a*t^2, so in your case

v = a*t, and
x = .5*a*t^2, two equations in two unknowns.
 
thanks
 
Awsom Guy said:
A bicyclist has a uniform acceleration of 2.30ms-2. What distance will he need to travel in order to attain a velocity of 21ms-2 if he started at rest?

Homework Equations


Hopefully this is the equation:
v2=u2+2as
Spinnor said:
v = v_0 + a*t, and
x = x_0 + v_0*t + .5*a*t^2, so in your case

v = a*t, and
x = .5*a*t^2, two equations in two unknowns.

uhh? :confused:

v2=u2+2as was the correct formula​
 
tiny-tim said:
uhh? :confused:

v2=u2+2as was the correct formula​

I find it more easy to memorize one formula and then manipulate as needed. It sticks with you longer?
 
Spinnor said:
I find it more easy to memorize one formula and then manipulate as needed. It sticks with you longer?

Hi Spinnor! :smile:

I strongly recommend against that.

In most problems, one of the three standard constant acceleration formulas will do the job immediately, and so they should all be learnt.

In an examination, you have to show your calculations, and it wil become obvious either that you don't know one of the formulas, or that you do know, but you've made the answer longer by choosing the wrong one … either way, you'll lose marks. :redface:
 
tiny-tim said:
Hi Spinnor! :smile:

I strongly recommend against that.

In most problems, one of the three standard constant acceleration formulas will do the job immediately, and so they should all be learnt.

In an examination, you have to show your calculations, and it wil become obvious either that you don't know one of the formulas, or that you do know, but you've made the answer longer by choosing the wrong one … either way, you'll lose marks. :redface:

Learn the formulas and not where they come from and in a year you will remember little. Learn the basic formulas and maybe a year from now those looking for help could still do the problems they come here for help?

To each his own.
 
Either way I am still hopeless with all the formulas. I've been taught to get the basic equation v2=u2+2as and derive it to get the other equations.
 
Learn all three equations. :wink:

They're surprisingly easy to remember. :smile:
 
  • #10
Yeah I know, I do prefer that. That is what I have done :)
 
  • #11
To answer your original post, your answer is wrong.

You need to understand what the variables in the formulas mean. In the equation you used, what does u represent? Does it make sense to set u=2.30 m/s^2 as you did?
 
  • #12
u should equal to 0 right.
 
  • #13
Your methodology is correct, except you need to rethink what the initial velocity is.
 
  • #14
Awsom Guy said:
u should equal to 0 right.

right! :biggrin:
 
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