Chem Question: Isoelectronic Ions and Ca Notation Explained

  • Thread starter Thread starter courtrigrad
  • Start date Start date
  • Tags Tags
    Chem
AI Thread Summary
Isoelectronic ions contain the same number of electrons, which can be determined by subtracting the net charge from the atomic number. For example, argon (Ar) has 18 electrons, while chlorine (Cl-) and calcium (Ca+2) also have 18 electrons when accounting for their charges, making them isoelectronic with Ar. The notation Ca: [Ar]4s² indicates that calcium has the same electron configuration as argon plus two additional electrons in the 4s sublevel. If calcium loses these two valence electrons, it becomes isoelectronic with neutral argon. Understanding this notation is essential for clarity in chemistry discussions and exams.
courtrigrad
Messages
1,236
Reaction score
2
How do you know whether a group of ions is isoelectronic? Also what does this notation mean:

Ca: [Ar]4s^{2}?

Thanks
 
Physics news on Phys.org
courtrigrad said:
How do you know whether a group of ions is isoelectronic? Also what does this notation mean:

Ca: [Ar]4s^{2}?

Thanks
An atom or ion is isoelectonic with another atom or ion if the two contain equal numbers of electrons. This can easily be determined from the Atomic Numbers of the 2 species under consideration:
{Number of Electrons} = {Atomic Number} - {Net Charge}

Thus, for a neutral atom, the number of electrons equals the Atomic Number. For example, the neutral atom Ar with Atomic Number (18) has 18 electrons. For the negative ion Cl-1 with charge (-1) and Atomic Number (17), the number of electrons is {(17) - (-1)}=(18). For the positive ion Ca+2 with charge (+2) and Atomic Number (20), the number of electrons equals {(20) - (+2)}=(18).

The terminology:
Ca: [Ar]4s^{2}
indicates that the neutral Ca atom has the same electron energy/orbital structure as neutral Ar PLUS 2 ADDITIONAL ELECTRONS in the "s" Sublevel of the 4th Energy Level (Principle Quantum Number = 4). From this indication, it can be determined that if Ca loses its 2 valence electrons (i.e., the 2 4s2 electrons), the resulting Ca+2 ion will be isoelectronic with the neutral Ar atom.


~~
 
Last edited:
xanthym said:
The terminology:
Ca: [Ar]4s^{2}
indicates that the neutral Ca atom has the same electron energy/orbital structure as neutral Ar PLUS 2 ADDITIONAL ELECTRONS in the "s" Sublevel of the 4th Energy Level (Principle Quantum Number = 4).
This has been said but not written so simply for clarity:

Ca: 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2} means the same as Ca: [Ar]4s^{2}

It is just a short hand and easier to write but use the long hand in exams or you lose marks. :smile:

The Bob (2004 ©)
 
Nope.It would be ridiculous,if one of the teachers would not accept the shorthanded notation...
But i know that there are a lotta dumb profs out there...

Daniel.
 
dextercioby said:
Nope.It would be ridiculous,if one of the teachers would not accept the shorthanded notation...
But i know that there are a lotta dumb profs out there...

Daniel.
Personally I do not understand why I cannot short hand but there is no mark for it in the mark scheme so it is better to be safe than sorry. :smile:

The Bob (2004 ©)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top