Chemical element and chemical property

AI Thread Summary
Atoms of the same chemical element, known as isotopes, have the same number of protons and thus share identical chemical properties despite differing in neutron count and atomic weight. The chemical properties are primarily determined by the electrons, which are responsible for atomic bonding. While isotopes exhibit slight variations in electron binding energy due to mass differences, these do not result in significantly different chemical behaviors. Additionally, differences in spectral lines can be utilized for isotopic separation. Overall, nuclear properties may vary with atomic mass, but the fundamental chemical properties remain consistent among isotopes.
mike2007
Messages
46
Reaction score
0
Is it possible for atoms of the same chemical element to have different chemical properties?

My attempt
Isotopes of an element differ from one another by the number of neutrons in the nucleus. They have same number of proton in the nuclei so they have the same chemical properties but not same atomic weight.
 
Physics news on Phys.org
The 'chemical' properties of an atom are governed by the electrons, since it is they that participate in the atomic bonding.

There are very slight differences in electron binding energy as a result of the mass differences between isotopes, but they do not mean very different chemical properties. Related to this is the difference in spectral lines and one can take advantage of this difference of isotopic separation.

http://en.wikipedia.org/wiki/SILEX
http://www.silex.com.au/

The nuclear properties, such as neutron absorption cross-section or binding energy, do change with atomic mass.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top