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Homework Help: Chemical reaction: Cu(s)+2H+(aq)--> Cu2+ (aq) + H2 (g)

  1. Nov 8, 2004 #1
    Chemical reaction: Cu(s)+2H+(aq)----> Cu2+ (aq) + H2 (g)

    Cu(s)+2H+(aq)----> Cu2+ (aq) + H2 (g)
    Do we have this reaction?
    If yes, is it a displacement reaction?
    If no, is something about the oxiding power of particles?
    Could you explain it to me ?
    Best regards
     
  2. jcsd
  3. Nov 8, 2004 #2

    HallsofIvy

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    I see no reaction here at all! You start with separate Copper and Hydrogen and you end with separate Copper and Hydrogen. Are you counting 2Cu--> Cu2 and 2H--> H2 as "reactions"?
     
  4. Nov 8, 2004 #3
    It's an ionic equation! Actually, it is supposed to like this:

    2Cu (s) + 2H+ (aq) = Cu2+ (aq) + H2 (g)

    I can't exactly recall where I've seen this.
     
    Last edited: Nov 8, 2004
  5. Nov 9, 2004 #4
    Does this reaction exist?
     
  6. Nov 9, 2004 #5

    ek

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    Isn't copper being oxidized?

    Is this not an oxidation-reduction reaction?

    Am I really that bad at chemistry?

    :rofl:
     
  7. Nov 9, 2004 #6
    In my mind, I'm quite sure it is not a displacement reaction.
    Hydrogen is above copper in the reactivity series.
    I haven't learnt any oxid redox reaction so far, so I want to consult about the concept of it.
    Less reactive still can reduce more reactive metal in redox reaction?
     
  8. Nov 9, 2004 #7

    ek

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    I don't think this reaction is possible.

    Copper metal will not oxidize when put in H+ ions, it will reduce because it is a stronger oxidizing agent.

    The two half-cells:

    Cu2+ + 2e- -> Cu
    H2 -> 2H+ + 2e-

    And together:

    Cu2+ + H2 -> Cu + 2H+

    This reaction WILL occur, the one you gave WILL NOT.

    Take my info with a grain of salt though. I do Physics/Astronomy, not Chemistry. But I do have a background in chem, so I'm not clueless.
     
  9. Nov 9, 2004 #8
    Ya! This is a displacement reaction!
     
  10. Nov 9, 2004 #9

    ek

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    I've never heard it referred to as that, but if that's what your teacher calls it, ok.
     
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