Chemistry - Ideal gas equation question

AI Thread Summary
The discussion revolves around calculating the new pressure of oxygen in a steel gas bottle after releasing 700g of gas. The ideal gas equation, PV = nRT, is applied, noting that volume and temperature remain constant. Participants clarify that the pressure can be determined using the ratio of initial and final moles of gas. The final calculation yields a new pressure of approximately 5482 Pa after the gas release. This demonstrates the application of the ideal gas law in practical scenarios.
david18
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A steel gas bottle contains 4500g of oxygen. The pressure of the gas inside the bottle is 6492Pa. If 700g of gas are slowly released from the bottle, what will be the new pressure of the remaining gas? (Assume that the temperature stays constant when the oxygen is released)

I'm having trouble with this question as I can only find PV but not P on its own.

Thanks
 
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Use PV = nRT before and after the release.
You know the change in 'n' the number of moles, and V stays the same, volume of bottle doesn't change.
 
Would you take the Pa/mol and multiply that by the final mol. I get 5429 Pa. I am learning this subject as well, so I am curious.
 
PV = nRT
V is constant, T is constant, R is constant (obviously!) so all you need is P/n before and after. YOu can work in totally arbitrary units for n since we are cancelling thme out

P1/n1 = P2/n2
P2 = P1 n2/n1 = 6492 * (4500-700)/4500 = 5482 Pa
 
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