Cherenkov Radiation in a Vacuum Tube

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SUMMARY

The discussion centers on the phenomenon of Cherenkov radiation in 6L6 vacuum tubes. Chris Maness calculates the relativistic velocity of electrons in the tube, concluding that the speed is insufficient for Cherenkov radiation to occur, as the maximum kinetic energy of 500 eV translates to a velocity of approximately 1.3 x 107 m/s. Instead, the blue dot observed is attributed to fluorescence, with photon energies around 4-4.5 eV, or ionization if the color is more pinkish, indicating a gassy power tube.

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  • Knowledge of vacuum tube operation and characteristics
  • Familiarity with the concept of Cherenkov radiation
  • Basic principles of fluorescence and ionization in gases
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Someone on another forum shared with me that a 6L6 vacuum tube exhibits a blue dot when in operation that is supposed to be Cherenkov radiation. I say nay, as I have worked out the relativistic velocity using $$KE={ m }_{ 0 }{ c }^{ 2 }\left[ \frac { 1 }{ \sqrt { 1-\frac { { v }^{ 2 } }{ { c }^{ 2 } } } } -1 \right] $$. The plate voltage is 500V max, so I used 500eV for the KE. This works out to $$8x10^{-17}$$Joules. Solving for v, I get v=$$1.3x10^{7}m/s$$. If the speed of light in glass is $$\frac{c}{n}$$, where n=The index of refraction of glass (I will assume 1.5). Then these electrons are not fast enough for Cherenkov radiation. Am I on target here?

Thanks,
Chris Maness
 
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Its more likely some sort of ionization - and the spectrum is blue because the photon energies are around 4-4.5 eV.
 
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