Chromium Ions in Water: Balancing Cr3++ and OH- to Form Cr(OH)3

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The discussion centers around the chemical reaction Cr3++OH-→Cr(OH)3, with participants debating the correct coefficients for balancing the equation. The main point of contention is whether the correct coefficient for OH- should be 3 or 9. One participant argues that since each OH- has a -1 charge, three OH- ions are needed to balance the +3 charge of Cr, resulting in Cr + 3OH- → Cr(OH)3. Another participant suggests that for proper balancing, the equation should reflect 3Cr + 9OH- → 3Cr(OH)3, but this is later simplified to the correct form by dividing coefficients by 3. The importance of balancing both atoms and charges in chemical equations is emphasized, highlighting that both mass and charge conservation must be maintained in reactions.
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Cr3++?OH-→ Cr(OH)3

I think it should be 9 but the mark scheme says 3 but accept correct multiples because the 3+ charge has to be canceled by 3- and this has to produce 3 O
 
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What are you wanting to know? ...Are you wondering about the coefficient in front of the OH?
Because that is 3.

Each OH- has a charge of -1 (it's one of those polyatomic ions).
So the Cr+3 and 3 OH- ions cancel each other out and is neutral overall.

I hope I answered what you wanted to know...
Sorry if I didn't realize you were asking something else!
 
Lo.Lee.Ta. said:
What are you wanting to know? ...Are you wondering about the coefficient in front of the OH?
Because that is 3.

Each OH- has a charge of -1 (it's one of those polyatomic ions).
So the Cr+3 and 3 OH- ions cancel each other out and is neutral overall.

I hope I answered what you wanted to know...
Sorry if I didn't realize you were asking something else!

I still think its dodgy because you are producing 3 OH so need 9 like in electrolysis, where 2O2-→4e- + O2 on the principle of that it should be 9 but I'm thinking the question itself is incorrect because it should be 3Cr3++9OH-→Cr(OH)3
 
You just have to make sure there is the same number of elements on each side.


3Cr+3 + 9OH-→Cr(OH)3

This isn't balanced because there are 3 Cr's on the left, and only 1 Cr on the right.
And on the left, there's 9 OH's, but on the right, there's only 3 OH's.

To balance this, you could add a 3 coefficient to the right side.

Then you'd have:

3Cr + 9OH --> 3Cr(OH)3

Now there are 3 Cr's on each side, and 9 OH's on each side.

*But this can be simplified further.
Just divide each coefficient by 3, and you'd get the correct formula:

Cr + 3OH --> Cr(OH)3
 
You are both inconsistent in treating charges - please always list them, as they are as important as atoms are. Reaction equation needs to have both atoms and charge balanced - atoms reflect mass conservation, charge reflects charge conservation
 
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