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**Start Again!!!**

Anyways, you are saying that the [itex]P_{VCCS}\,=\,163.4\,W[/itex] is correct?

Let's just start from the beginning!

http://img291.imageshack.us/img291/5479/chapter2problem22wy5.jpg [Broken]

[tex]i\,=\,2\,v_0\,+\,10\,A[/tex]

Right?

[tex]v_o\,=\,i\,R[/tex]

[tex]v_o\,=\,\left(2\,v_0\,+\,10\right)\,(4\Omega)[/tex]

Right?

[tex]v_0\,=\,8\,v_0\,+\,40[/tex]

So...

[tex]v_0\,=\,-\frac{40}{7}\,V[/tex]

Right?

I need to find the power dissipated by the controlled source. [itex]P_{VCCS}\,=\,?[/itex]

So, I need to use the EQs [itex]P\,=\,v\,i[/itex] or [itex]P\,=\,\frac{v^2}{R}[/itex], right?

The i should only be for the contribution by the VCCS. So, [itex]i_{VCCS}\,=\,2\,V_0[/itex], right?

Now what do I do, assuming the above is all right?

[tex]P\,=\,I\,V\,=\,I_{VCCS}\,V_{VCCS}[/tex]

[tex]I_{VCCS}\,=\,2\,V_0\,=\,2\,\left(-\frac{40}{7}\right)\,=\,-\frac{80}{7}\,\approx\,-11.43\,A[/tex]

Does this seem right?

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