Circuit analysis - Finding the currents

AI Thread Summary
The discussion revolves around solving a circuit analysis problem using Kirchhoff's laws to find three unknown currents. The participant initially misinterprets the sign of a term in their equation but learns that the direction of current flow affects voltage signs. They clarify that the current direction is determined by the battery voltages, even if not numerically specified. The conversation highlights the importance of understanding current flow and voltage drops in circuit analysis. Ultimately, the participant realizes the direction of current I_2 is clear based on the circuit configuration.
hadoque
Messages
39
Reaction score
1

Homework Statement



Find the three currents in the image.

Homework Equations


Khirkoffs laws
Sum of currents equal zero.
The potentials around a closed loop add up to zero.
The equations given in the solution are
-2I_1 + 12I_2+6=0
-12I_2+8 = 0
I_1+I_2+I_3=0

The Attempt at a Solution



When I tried to solve this I had the first equation to be
-2I_1-12I_2+6=0, by doing a potential walk round the left subcircuit (?).
Why should the second term be positive?
 

Attachments

  • circuit.gif
    circuit.gif
    3.9 KB · Views: 501
Physics news on Phys.org
hadoque said:

Homework Statement



Find the three currents in the image.

Homework Equations


Khirkoffs laws
Sum of currents equal zero.
The potentials around a closed loop add up to zero.
The equations given in the solution are
-2I_1 + 12I_2+6=0
-12I_2+8 = 0
I_1+I_2+I_3=0

The Attempt at a Solution



When I tried to solve this I had the first equation to be
-2I_1-12I_2+6=0, by doing a potential walk round the left subcircuit (?).
Why should the second term be positive?

By convention, when you have the current going down through a component, the top of the component will be + and the bottom will be -. Since you are going around the loop on the left against the direction labelled for I1, it is a negative voltage term. Since you are continuing around that clockwise loop on the left and go through the middle resistor in the same direction as the current arrow shown, it is a + voltage drop.
 
Ok, but how do I know the current is going down in I_2, besides the arrow? If the problem didn't give the currents directions, I should still be able to solve it! Is it that the right battery has a higher voltage? If so, what if the problem didn't give the battery voltage in numerics, but instead gave, say, the voltage v_1 and v_2. Then I wouldn't know which one has the higher voltage...
 
Ok, sorry. i just realized I was thinking wrong about the circuit, there is only one option for the direction of I_2.

Thanks
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top